fix: show multi-plate jobs in À planifier until all plateaux are scheduled

app.py

@@ -1324,9 +1324,18 @@ def planning():
     conn = get_db()
     printers  = [dict(r) for r in conn.execute('SELECT * FROM printers ORDER BY id').fetchall()]
     unscheduled = conn.execute('''
-        SELECT j.*, c.name as client_name
+        SELECT j.*, c.name as client_name,
+               COALESCE((SELECT COUNT(*) FROM print_slots ps
+                         WHERE ps.job_id=j.id
+                         AND ps.status NOT IN ('cancelled','failed')), 0) as scheduled_plates,
+               (COALESCE(j.order_qty,1) + COALESCE(j.pieces_per_plate,1) - 1)
+               / COALESCE(j.pieces_per_plate,1) as total_plates_needed
         FROM jobs j LEFT JOIN clients c ON j.client_id=c.id
-        WHERE j.id NOT IN (SELECT DISTINCT job_id FROM print_slots WHERE status NOT IN ('cancelled','failed'))
+        WHERE (COALESCE(j.order_qty,1) + COALESCE(j.pieces_per_plate,1) - 1)
+              / COALESCE(j.pieces_per_plate,1)
+              > COALESCE((SELECT COUNT(*) FROM print_slots ps
+                          WHERE ps.job_id=j.id
+                          AND ps.status NOT IN ('cancelled','failed')), 0)
         ORDER BY j.created_at DESC LIMIT 20''').fetchall()
     blocks = conn.execute(
         "SELECT * FROM calendar_blocks"